How to find area of triangle when coordinates are given?
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You know that AB x AC is a vector perpendicular to the plan ABC such that |AB x AC|= Area of the parallelogram ABA’C. Thus this area is equal to ½ |AB x AC|.
enter image description here
From AB= (x2−x1,y2−y1); AC= (x3−x1,y3−y1), we deduce then
Area of ΔABC =
1
2
[(x2−x1)(y3−y1)−(x3−x1)(y2−y1)]
enter image description here
From AB= (x2−x1,y2−y1); AC= (x3−x1,y3−y1), we deduce then
Area of ΔABC =
1
2
[(x2−x1)(y3−y1)−(x3−x1)(y2−y1)]
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