How to find divisior when divident and quocent is given
Answers
Answer:multiply simply
Step-by-step explanation:
Divident = Divisor × Qoutient + Reminder
If Divident and Qoutient is given , we can find the Divisor by ,
Divisor = Divident - Reminder ÷ Qoutient
For eg :
On dividing x³-3x²+x+2 by a polynomial g(x) , the quotient and reminder are x-2 and -2x+4 respectively. Find g(x)
Answer :
= x³-3x²+x+2 = g(x) (x-2) + (-2x+4)
( Here (x-2) is qoutient and (-2x+4) is reminder )
Transforming -2x+4 to LHS
ie; x³-3x²+x+2 + 2x-4 = g(x) (x-2)
On transforming -2x+4 to LHS -ve will be changed to positive and +ve will be changed to negetive
ie; x³-3x²+3x-2 = g(x) (x-2)
( 3x-2 is (2x+x) and (+2-4) )
∴ x³-3x²+3x-2 ÷ x-2 = g(x)
( On taking multiplied by x-2 to LHS it will be changed to divided by x-2)
∴ g(x) = x²- x +1
On dividing x³-3x²+3x-2 ÷ x-2 you will get the divisor as x² - x + 1