Two years ago, a man's age was three times the square of his son's ages. three years hence, his age will be four times his son's age. find their present ages.
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It's easy
X-2 = 3(x-2)whole square
This is equation 1
X+3 = 4(x+3-2)whole square
This is equation 2.
I hope u know how to solve the two quadratic equations
X-2 = 3(x-2)whole square
This is equation 1
X+3 = 4(x+3-2)whole square
This is equation 2.
I hope u know how to solve the two quadratic equations
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