Question

How to find equation of directrix of parabola y^2+4y+4x+2=0?

Answer 1

Given equation of parabola
y^2+4y+4x+2=0
(y+2)^2 +4x +2 =0
(y+2)^2 = -4(x -1/2)
its diretrix is x-1/2 =1
x= 3/2
hope its helps

Answer 2

Given equation of parabola

y^2+4y+4x+2=0

(y+2)^2 +4x +2 =0

(y+2)^2 = -4(x -1/2)

its directrix is x-1/2 =1

x= 3/2  

hope its helps