Math, asked by ibrahimshakhan06, 10 days ago

how to find if length of a rectangle is twice to its breadth if its perimeter is 48 meter then find it's length and breadth​

Answers

Answered by aryashekhardutta
1

Step-by-step explanation:

Let the breadth of the rectangle be x m

"length of a rectangle is twice to its breadth"

Therefore, the length of the rectangle = (2x)m

Formula for the perimeter of a rectangle = 2(l + b)

Perimeter of the rectangle = 2 (l + b) = 48m

Therefore,

2 (l + b) = 48

= 2 (2x + x) = 48    {Substituting the values}

= 2 × 3x = 48

= 6x = 48

= x = 48/6 = 8m

Therefore,

Breadth = x = 8m

Length = 2x = 2 × 8 = 16m

Here is your answer. Hope it helps!

Answered by kv44489
0

Answer:

Let the breadth be x

then, the length be 2x

perimeter of rectangle = 2( length + breadth )

48 meter = 2(x+2x)

48 meter = 2(3x)

48 meter = 6x

48 / 6 = x

8 meter = x

breadth = x = 8 meter

length = 2x = 2×8 = 16meter

I hope it's help you

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I solve this question with myself not

like paste from internet

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