how to find interior angles of a triangle
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1. The sum of the internal angles equals 180º ...A + B + C = 180º 2. The 'sine rule' ...3. The 'cosine rule' ... a² = b² + c² - 2bc cosA or b² = a² + c² - 2ac cosB or c² = b² + a² - 2ba cosCWe will now use an example to show how these rules are applied to solve a triangle when two angles and one side length are given. Example: Solve this triangle for the unknown internal angle and sides:Step 1: Calculate the unknown angle. The sum of the internal angles equals 180º ... A + B + C = 180ºso C = 180º - (A+B) = 180º - (30º+70º) = 180º - 100º = 80ºStep 2: Use the sine rule to find one unknown side. NOTE: The sine rule is easier to use than the cosine rule.To find side 'c' with the sine rule: Step 3: Use the sine rule again to find the other unknown side. To find side 'a' with the sine rule:
Rakeshrake:
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Sum of all the angles must be 180 now give eqnlet the angles in the triangle are I ratio of 1:2:3 then let the number be x then 1x+2x+3x=180 solve the equation to get answers
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