Question

How to find length and breadth of rectangle when area and perimeter is given?

Answer 1

2(L+B) is the perimeter and let it be equal to x
so
2(L+B)=x

Area of Rectangle is L×B
L×B=y
B=y/L

Here we know the values of x and y
so

2(L+B)=2(L+y/L)=x

So from this equation by substituting the values of x and y we can get L and B

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Answer 2

Answer:

this is my first answer

Step-by-step explanation:

let the area be 60 and perimeter be 38

so, 2(l+b)= 38

l+b = 38/2= 19

l×b = 60

then take (l+b)²=19²

(l+b)²=361

l²+b²+2lb=361

l²+b²=361-2lb

l²+b²=361-2×60

l²+b²=361-120=241

(l-b)²-2lb=241

(l-b)²=241-120=121

(l-b)²=121

(l-b)=121the root

l-b=11

l=11+b

l+b=19

11+b+b=19

11+2b=19

2b=19-11

b=8/2=4

l=11+b=11+4=15