how to find N-H bond energy from haber' process
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Explanation:
ΔH=[ΔH(N≡N)+3×ΔH(H−H)]−[6ΔH(N−H)]
945+3×435.0−6×389.0=−83.64kJ
Heat formation of NH3=ΔH/2=−83.64/2=−41.82kJ mol −1
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