Question

how to find nearest perfect square number​

Answer 1

Answer:

Square the integers next to the root. Let r be int(sqrt(double(number))+0.5) . Then you need to check which of (r-1)*(r-1) , r*r and (r+1)*(r+1) is the nearest to number . That's all

Step-by-step explanation:

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Answer 2

Answer:

Add the like1 and2 then add 3 and4 then 5and6