Question

how to find out thr number of atoms present in 34 g of NH3???

Answer 1

Explanation:

at first we find out molecular mass of NH3

so molecular mass of NH3 is 17g.

17 gram of NH3 is equal to one mole of NH3.

so in 34 gram of NH3 is equal to 2mole.

since one mole of NH3 contain 6.022 into 10 power 23 atom so number of atom in 34 gram of NH 3 =2*6.022*10^23

=12.044*10^23

Answer 2

Find out molecular mass of $NH_{3}$ , which is 17g.

17 g of $NH_{3}$ = one mole of $NH_{3}$

⇒ 34 gram = 2 mole.

= 12.044 * $10^{23}$