How to find perpendicular lrngth on a tight angled triangle?
Answers
Answered by
0
In right angled triangle,
(hypotenuse)² = (perpendicular)² + (base)²
=> h² = p² + b²
=> p² = h² - b²
=> p = √(h² - b²)
Hope it'll help...:)
(hypotenuse)² = (perpendicular)² + (base)²
=> h² = p² + b²
=> p² = h² - b²
=> p = √(h² - b²)
Hope it'll help...:)
Answered by
0
https://brainly.in/question/1799093
Similar questions