How to find radius of bcc crystal structure?
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Draw a diagram of body centred cubic (bcc) packing
Identify the bcc unit cell
Analyze the geometry of the bcc unit cell
Calculate geometric parameters of the bcc packing
If the edge is a, then we have:
fd2 = a2 + a2 = 2 a2
bd2 = fd2 + a2
= a2 + a2 + a2
= 3 a2
Atoms along the body diagonal (bd) touch each other. Thus, the body diagonal has a length that is four times the radius of the atom, R.
bd = 4 RThe relationship between a and Rcan be worked out by the Pythagorean theorem:
(4 R)2 = 3 a2Thus,4 R = sqrt(3) a
or
a = 4R/sqrt(3)
Identify the bcc unit cell
Analyze the geometry of the bcc unit cell
Calculate geometric parameters of the bcc packing
If the edge is a, then we have:
fd2 = a2 + a2 = 2 a2
bd2 = fd2 + a2
= a2 + a2 + a2
= 3 a2
Atoms along the body diagonal (bd) touch each other. Thus, the body diagonal has a length that is four times the radius of the atom, R.
bd = 4 RThe relationship between a and Rcan be worked out by the Pythagorean theorem:
(4 R)2 = 3 a2Thus,4 R = sqrt(3) a
or
a = 4R/sqrt(3)
Raha57:
nice answering
will you pls help me too
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