How to find roots of an equation Root3x squared-2x-root3
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√3x² - 2x - √3
√3x² - 3x + x - √3
√3x ( x - √3 ) + 1 ( x - √3 )
( x - √3 ) ( √3x + 1 )
° ( x - √3 ) = 0
x = √3
° ( √3x + 1 ) = 0
x = - 1/√3
Steps to Solve ( Middle term Splitting ) :-
• Multiply the coefficient of x² to Constant term.
Here ,
√3 × √3 = 3
• Now Taking LCM of 3
3 = 3 × 1
• Now either by adding 3 and 1 Or by subtracting we have to get the coefficient of x that is - 2
and we can get only by subtracting 3 from 1 ...
• By taking common and equating them by 0 , we get the Roots of the equation.
√3x² - 3x + x - √3
√3x ( x - √3 ) + 1 ( x - √3 )
( x - √3 ) ( √3x + 1 )
° ( x - √3 ) = 0
x = √3
° ( √3x + 1 ) = 0
x = - 1/√3
Steps to Solve ( Middle term Splitting ) :-
• Multiply the coefficient of x² to Constant term.
Here ,
√3 × √3 = 3
• Now Taking LCM of 3
3 = 3 × 1
• Now either by adding 3 and 1 Or by subtracting we have to get the coefficient of x that is - 2
and we can get only by subtracting 3 from 1 ...
• By taking common and equating them by 0 , we get the Roots of the equation.
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