Question

how to find sin15.cos15

Answer 1

Step-by-step explanation:

APPLYING THE FORMULA

2sinAcosA = sin2A

ATQ

sin 15 cos 15 = sin(2*15)/2

=> sin 30 /2

=>1/4

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Answer 2

sin 2x = 2 sin x cos x

sin (2×15) = 2 sin 15 cos 15

sin 30 = 2 sin 15 cos 15

1/2 = 2 sin 15 cos 15

therefore sin 15 cos 15 = 1/2*1/2

= 1/4

= 0.25