How to find the area using Heron's formula is AB= 9m, BC=40m and angle B= 90°?
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Step-by-step explanation:
In triangle ABC,
AB=9m
BC=40m
B=90°
by the pythagoras theorem,
AC^2=AB^2+BC^2
AC^2=9^2+40^2
AC^2=81+1600
AC^2=1681
AC^2=41^2
AC^2=41m
a,b,c are sides of triangle ABC.
S=a+b+c/2
=9+40+41/2
=90/2
=45m
Area=under root S(S-a)(S-b)(S-c)
=under root 45(45-9)(45-40)(45-41)
=under root 45(36)(5)(4)
=under root (45)(720)
=under root 32400
=180m^2
Therefore,the area of triangle ABC is 180m^2.
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