HOW TO FIND THE GOLD NUMBER OF AN ELECTROLYTE?
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Hardy schulze rule
“Greater is the valency of coagulating ion added, the greater is its power to cause precipitation ”. In the coagulation of a negative colloidal solution the coagulating power is as :
All^3++ > Ba^++ > Na^+
In the coagulation of a positive colloidal solution the following power is as :
[ Fe(CN)6]^4- , Po4^3-, SO4^2- , Cl^-
Protection of colloids:
Lyophobic colloidal solutions are coagulated on addition of electrolytes while lyophillic colloidal solutions are not coagulated by electrolyte . If small amount of lyophillic colloidal solution is present along with a lyophobic colloidal solution, the addition of a small amount of electrolyte does not coagulate either of them. It means presence of lyophillic colloidal solution prevents a lyophobic colloidal solution from coagulation. This phenomenon is known as protection & the lyophillic colloid used for this purpose is known as protective colloid.
When a lyophillic colloid is added to a lyophobic colloidal solution, the particles of lyophobic colloidal solution adsorbs the particles of lyophillic colloid around them & behaves like lyophillic colloidal solution. This prevent them from coagulation.
Gold Number:
” The Gold number is defined as the number of milligrams of the protective colloid in dry state which when added to 10 ml of a colloidal solution of gold, prevents the gold solution from coagulation on addition of 1 ml of 10% NaCl solution.”
Gold number of different lyophillic colloids are different. Lesser is the gold number greater is the protective power.
Question : The coagulation of 100 ml of a colloidal solution of gold is completely prevented by adding 0.25 gm of starch to it before adding 10 ml of 10% NaCl solution. Find out the gold number of starch ?
solution:
100 ml gold solution requires = 0.25 gm starch ( i.e 250 mg starch)
10 ml gold solution requires = 250 × 10 / 100 = 25 mg
10ml of 10 % NaCl solution is added to 100 ml gold solution. Thus 1 ml of 10% NaCl solution been added to 10 ml solution of gold.
Question: The coagulation of 10 ml of a colloidal solution of gold can be completely stopped by the addition of 0.025 gms of starch before the addition of 1 ml of 10% NaCl solution. What is the gold number ?
solution:
Coagulation of 10 ml of colloidal solution of gold can be stopped by the addition of
1 ml of 10% NaCl = number of milligrams of starch
= 0.025 gm = 0.025 × 1000 mg = 25 mg.
HOPE IT HELPS...
PLEASE PLEASE MARK AS BRAINLIEST.
“Greater is the valency of coagulating ion added, the greater is its power to cause precipitation ”. In the coagulation of a negative colloidal solution the coagulating power is as :
All^3++ > Ba^++ > Na^+
In the coagulation of a positive colloidal solution the following power is as :
[ Fe(CN)6]^4- , Po4^3-, SO4^2- , Cl^-
Protection of colloids:
Lyophobic colloidal solutions are coagulated on addition of electrolytes while lyophillic colloidal solutions are not coagulated by electrolyte . If small amount of lyophillic colloidal solution is present along with a lyophobic colloidal solution, the addition of a small amount of electrolyte does not coagulate either of them. It means presence of lyophillic colloidal solution prevents a lyophobic colloidal solution from coagulation. This phenomenon is known as protection & the lyophillic colloid used for this purpose is known as protective colloid.
When a lyophillic colloid is added to a lyophobic colloidal solution, the particles of lyophobic colloidal solution adsorbs the particles of lyophillic colloid around them & behaves like lyophillic colloidal solution. This prevent them from coagulation.
Gold Number:
” The Gold number is defined as the number of milligrams of the protective colloid in dry state which when added to 10 ml of a colloidal solution of gold, prevents the gold solution from coagulation on addition of 1 ml of 10% NaCl solution.”
Gold number of different lyophillic colloids are different. Lesser is the gold number greater is the protective power.
Question : The coagulation of 100 ml of a colloidal solution of gold is completely prevented by adding 0.25 gm of starch to it before adding 10 ml of 10% NaCl solution. Find out the gold number of starch ?
solution:
100 ml gold solution requires = 0.25 gm starch ( i.e 250 mg starch)
10 ml gold solution requires = 250 × 10 / 100 = 25 mg
10ml of 10 % NaCl solution is added to 100 ml gold solution. Thus 1 ml of 10% NaCl solution been added to 10 ml solution of gold.
Question: The coagulation of 10 ml of a colloidal solution of gold can be completely stopped by the addition of 0.025 gms of starch before the addition of 1 ml of 10% NaCl solution. What is the gold number ?
solution:
Coagulation of 10 ml of colloidal solution of gold can be stopped by the addition of
1 ml of 10% NaCl = number of milligrams of starch
= 0.025 gm = 0.025 × 1000 mg = 25 mg.
HOPE IT HELPS...
PLEASE PLEASE MARK AS BRAINLIEST.
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