Math, asked by aoumau1562, 1 year ago

In a right triangle abc bd divides triangla abc into two equal perimeter triangles.find bd if ac=10 bc=8

Answers

Answered by kinggAbdul1
0
the equal perimerter of triangle
Answered by vchandrajaiswal
1

Answer:

in triangle abc, let cd=y & bd =x.

if cd=y, then ad=10-y

perimeter of triangle abd= perimeter of triangle bdc (given)

therefore, 6+10-y+x=x+y+8

16-y=y+8

y=8/2

y=4

by cosine rule

cos c=8^2+4^2-x^2/2*8*4

8/10=64+16-x^2/64

4/5=80-x^2/64

256/5=80-x^2

x^2=80-256/5

5x^2=400-256

144/5=x^2

x=12/under root 5

Step-by-step explanation:

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