In a right triangle abc bd divides triangla abc into two equal perimeter triangles.find bd if ac=10 bc=8
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the equal perimerter of triangle
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Answer:
in triangle abc, let cd=y & bd =x.
if cd=y, then ad=10-y
perimeter of triangle abd= perimeter of triangle bdc (given)
therefore, 6+10-y+x=x+y+8
16-y=y+8
y=8/2
y=4
by cosine rule
cos c=8^2+4^2-x^2/2*8*4
8/10=64+16-x^2/64
4/5=80-x^2/64
256/5=80-x^2
x^2=80-256/5
5x^2=400-256
144/5=x^2
x=12/under root 5
Step-by-step explanation:
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