How to find the largest 4 digit no. which is a perfect cube? pls help me fast and im getting prime factors as 3 x 3 x 11 x 101 . So can u pls help me with the next step. my exams r nearing.pls help me as fat as u can
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21*21*21 = 9261
22*22*22=10648
therefore largest 4 digit no. = (21)^3 = 9261
22*22*22=10648
therefore largest 4 digit no. = (21)^3 = 9261
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