Math, asked by ppiya, 1 year ago

how to find the log value of 1.23^1.5/11.2*23.5

Answers

Answered by zahraz

5

answer is 1.23^1.5/11.2*23.5 = 0.00518289

ppiya: but how dear?

ppiya: i want the method

Answered by kaushikravikant

6

y=log( 1.23)^1.5/(11.2)×23.5
y=log m^n=n log m
1.5/1.2×23.5 log 1.23
1.5/28.2 log 1.23
0.053191489 ×0.089905111
0.004782186

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