How to find the oxidation number of cr(oh) 3
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Step to calculate oxidation number for
- Identify the oxidation number of each element present in the compound.
- Accordingly, the oxidation number of Cr is +3, H is +3, and O is (-2 × 3) -6.
- As the given compound is neutral, the sum of its all oxidation number will be equal to zero.
- When all the oxidation number of the compound is added, it gives
(+3) + (-2×3) + (+3)
6 + (-6)
6-6 = 0
- Thus the oxidation number for is calculated as 0, as it is a neutral compound.
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Question 8.5 Calculate the oxidation number of sulphur, chromium and nitrogen in H2SO5,Cr2O7(2-) and NO3(-). Suggest structure of these compounds. Count for the fallacy.
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Explanation:
Cr(OH) 3
Oxidation number=
+3+3-6=
+3-3=0
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