how to find the sides of a triangle inside a square
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IN ENGLISH :
The area of the whole triangle is b*h/2. The area of the square is x2. The area of the triangle that is obtained by sliding together the two smaller triangles standing on the base is (b-x)*x/2. x = b*h/(b + h).
IN HINDI:
पूरे त्रिभुज का क्षेत्रफल b * h / 2 है। वर्ग का क्षेत्रफल x2 है। त्रिभुज का क्षेत्रफल जो आधार पर खड़े दो छोटे त्रिभुजों को एक साथ खिसकाकर प्राप्त किया जाता है (b-x) * x / 2 है। x = b * h / (b + h)
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Answer:
An isosceles triangle is inside a square. Its vertex touches a corner of the square. Its base angles touch the edges of the square. I only know the vertex angle and length of the sides of the square. How can I find the length of the triangle's base?
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