How to find the smallest and the largest 4 or 5 digit number that divides 8,9,45 number?
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find it by our own dude don't cheet
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The LCM of 3,12,18,24,30,36 is 360
We have the greatest five digit number : 99999
When 99999 is divided by 360, leaves the remainder 279
So, 99999−279=99720
Now here, we can see that
3−2=1, 12−11=1, 18−17=1, 24−23=1, 30−29=1, 36−35=1
The difference of divisors and their corresponding remainders is 1.
So, the required five digit number will be 1 less than $99720$$.
The required number is 99720−1=99719
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