Question

How to find the starting number between 300 and 500 divisible by 11

Answer 1

divide 300by 11 you get 3 remainder
11-3=8
300+8=308
500÷11 your remainder will be 5
500-5=495
a=308
an=495
d=11
an=a+(n-1)d
495=308 (n-1)11
495-308=(n-1)11
187/11=n-1
17-1=n
n=16 its your ans
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