how to find the sum of these to angles
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Note BD is the diameter.
So , a(BCD) = 90°
BC = CD ➡ a(BDC) = a(CBD) = 90/2 =45°
Note a(BDE) + a(EDC) = a(BDC) = 45°
Also , a(BAE) = a(BDC)
So , a(BAE) + a(EDC) = 45°
So , a(BCD) = 90°
BC = CD ➡ a(BDC) = a(CBD) = 90/2 =45°
Note a(BDE) + a(EDC) = a(BDC) = 45°
Also , a(BAE) = a(BDC)
So , a(BAE) + a(EDC) = 45°
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I think the answer as in circle rhombus has property like square
so BAC =45
the answer is 45° and point E is acting as mid point so angle BAE is 22.5°
similarly angle EDC
SUM = 45°
so BAC =45
the answer is 45° and point E is acting as mid point so angle BAE is 22.5°
similarly angle EDC
SUM = 45°
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