How to find the value of alpha in 6y2-7y+2
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where is alpha in it friend .....
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6ysquare- 7y+2= 0
by factorisation
6y^2-4y-3y+2=0
2y(3y-2)-1(3y-2)
(2y-1)(3y-2) =0
therefore zeroes are y= 1/2 and 2/3
by factorisation
6y^2-4y-3y+2=0
2y(3y-2)-1(3y-2)
(2y-1)(3y-2) =0
therefore zeroes are y= 1/2 and 2/3
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