how to find the value of sin 120 and cos120
Answers
Answered by
8
sin 120 = √3/2
cos 120= -1/2
sin120°= sin(1×90°+30°)=cos30°
cos(1×90°+30°)=-sin30°
cos 120= -1/2
sin120°= sin(1×90°+30°)=cos30°
cos(1×90°+30°)=-sin30°
mysticd:
How ?
(90+30)
Explain
(90°+30°)
put the value
wait
Edit
Answered by
10
sin120 can be written as sin(90+30)
and sin (90+x)= cosx
then sin(90+30) =cos30 =√3/2
similarly cos 120= cos(90+30) =-sin 30 =-1/2 [cos(90+x) =-sinx]
ans.
and sin (90+x)= cosx
then sin(90+30) =cos30 =√3/2
similarly cos 120= cos(90+30) =-sin 30 =-1/2 [cos(90+x) =-sinx]
ans.
minus kise aaya
ye formula hai
and sin ka
sin(90+x) =cos x hota hai
ok
cos ( 90 + 30 ) lie in second quadrant ,
In second quadrant sin is positive , cos is negative
ok thanks
and what about si
sin
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