whate is the dy/dx value of function log x
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Answered by
8
y= log x
dy/dx = 1/x
i hope this will help u
dy/dx = 1/x
i hope this will help u
Answered by
1
let y = log x
Differentiating both sides w.r.t x
=> dy/dx = 1/x
Hope it will help you
Differentiating both sides w.r.t x
=> dy/dx = 1/x
Hope it will help you
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