How to find the value of tan 30° geometrically?
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we know that tan 30° = 1/√3 = √3 / 3 units.
So we will draw a line of length √3 and then trisect that.
Draw a square ABCD of side 1 unit. Let AB be horizontal line. Join A and C. AC = √2.
Now draw a line perpendicular to AC at C. Use the geometric tools. Draw an arc of radius 1 unit to cut this perpendicular at E. Now CE = 1 unit. Join A and E. AE equals √3.
Now draw an arc with A as the center and AE as the radius to cut the extended line AB at F. So AF = √3.
Now use the trisection steps to trisect AF into AG, GH, HF. Each of them will be equal to 1/√3.
Trisection procedure is standard:
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Answered by
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so using this method we can find the value of tan 30
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