How to find the zeroes of quadratic p/n 4u^s+8u and verify the relationship between its zeroes and coefficients?
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Eqn: 4u^2+8u= 4u(u+2)=0
u=0, -2.
1.Sum of zeroes= alpha+beta=0-2=-2
=-b/a=-8/4=-2.
2.Product of zeroes= alpha*beta=0
=c/a=0/4=0.
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