Question

How to find the zeroes of quadratic p/n 4u^s+8u and verify the relationship between its zeroes and coefficients?

Answer 1

Eqn: 4u^2+8u= 4u(u+2)=0

u=0, -2.

1.Sum of zeroes= alpha+beta=0-2=-2

=-b/a=-8/4=-2.

2.Product of zeroes= alpha*beta=0

=c/a=0/4=0.

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Answer 2

Answer:

Step-by-step explanation:

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