Question

how to find the zeroes of rhe polynomial 4u^2+8u.

answer quickly.

Answer 1

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Answer 2

Answer:

Step-by-step explanation:

4u^2+8u

= 4u (u+2)

Either,

4u=0

u=o

Or,

u+2=0

u= -2

Hence, roots are (0, -2)

Hope this helps :)