Question

How to find value of log(3.98×10 raise to 2 )without using log table........

Answer 1

Hii
example log100=log(10)^2=2log10= 2(log5*2)=2(log5+log2)=2(0.7+0.3)=2. 5.1k
Logarithm Formulas. [math]\log_a (pqr) = \ log_a(p) + \log_a(q) + \log_a(r)[/math] 
(2) The logarithm (to base 10) of any number x is defined as the power N such that ... originating number, we look up on the table of logarithms the two entries which flank the value 
First memorize all the single digit base 10 logs. ... Log Base 10 of... Is equal to... 1, 0. 2, 0.301. 3, 0.477. 4, 0.602. 5, 0.698. 6, 0.778 ... Suppose you wanted to find the logarithm of ...

Answer 2

Answer:

The value of $log(3.98*10^2) =2.5798$

Explanation:

$log(a.b) = log(a) + log(b)$

$log(a^b) = b*log(a)$

So,

$log(3.98*10^2) = log(3.98) + log(10^2)$

$= log(3.98) - 2*log(10)$

Since

$log(1) = 0 \\log(2) = 0.3010$

$log 3 = 0.4771$

$log 4=0.6020$

$log(3.98*10^2)$

this is of the form $log(m*n)=log(m)+log(n)$

$log(3.98*10^2)=log(3.998)+log(10^2)$

the second term is of the form $log(a^n)=n*loga$

so,

$log(3.98*10^2)=log(3.98)+(2∗log(10))$

Considering it as log to base 10 since the base is not mentioned

$log(3.98*10^2)= 0.5798+(2*1)$

$=0.5798+(2)$

$=2.5798$