How to find volume strength of h2o2 when o2 volume is given?
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Volume or percentage strength of hydrogen peroxide is a term to express concentration of H2O2 in terms of volumes of oxygen gas based on its decomposition to form water and oxygen.
2H2O2 = 2 H2O + O2
Suppose we have a solution of M moles of H2O2 in 1L solution
From the reaction stoichiometry, 2 moles of H2O2 gives 1mol of oxygen or 22.4L at S.T.P
1mole of H2O2 = 11.2 L of O2
M mole of H2O2 = 11.2 x M L of O2
1L of H2O2 gives 11.2 x M L of O2
Vol strength of H2O2 = 11.2 x M
In terms of Normality, N
n factor for H2O2 is 2
N = M x n or N = M x 2
V S = 11.2 M = 11.2 x N/2 = 5.6 N
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