Math, asked by pradnya2406, 11 hours ago

how to find zeroes of 7x²-100​

Answers

Answered by AzureZ
1

Answer:

7x^{2} – 100

(\sqrt{7} )^{2} - (10)^{2}

(\sqrt{7}x-10) (\sqrt{7}+10)

x = \frac{10}{\sqrt{7} } , x = \frac{-10}{\sqrt{7} }  

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