Math, asked by sarveshero3, 11 months ago

How to find zeros of monomial with 100

Answers

Answered by keshav8gandhi62
0

Answer:Finding Zeros of Polynomials

Zeros of a polynomial can be defined as the points where the polynomial becomes zero on the whole. A polynomial having value zero (0) is called zero polynomial. The degree of a polynomial is the highest power of the variable x.

A polynomial of degree 1 is known as a linear polynomial.

The standard form is ax + b, where a and b are real numbers and a≠0.

2x + 3 is a linear polynomial.

A polynomial of degree 2 is known as a quadratic polynomial.

Standard form is ax2 + bx + c, where a, b and c are real numbers and a ≠ 0

x2+ 3x + 4 is an example for quadratic polynomial.

Polynomial of degree 3 is known as a cubic polynomial.

Standard form is ax3+ bx2 + cx + d, where a, b, c and d are real numbers and a≠0.

x3 + 4x + 2 is an example for cubic polynomial.

Similarly,

y6 + 3y4 + y is a polynomial in y of degree 6.

Points to remember:

0 could be a zero of polynomial but it is not necessarily a zero has to be 0 only.

All the linear polynomials have only one zero.

The zeros of the polynomial depends on its degree.

Also, read:

Factorization Of Polynomials

Polynomials Class 9

Polynomial For Class 10

Important Questions Class 10 Maths Chapter 2 Polynomials

Zeros of Polynomial Formula

Consider, P(x) = 4x + 5 to be a linear polynomial in one variable.

Let a be zero of P(x), then,

P(a) = 4k+5 = 0

Therefore, k = -5/4

In general, If k is zero of the linear polynomial in one variable; P(x) = ax +b, then

P(k) = ak+b = 0

k = -b/a

It can also be written as,

Zero of Polynomial K = -(Constant/ Coefficient of x)  

Example

Example: What is the value of a if degree of polynomial x3 + xa-4 + x2 + 1 is 4?

Degree of a polynomial P(x) is the highest power of x in P(x).

Therefore, xa-4  = x4

a-4 = 4, a = 4+4 =8

Therefore, the value of a is 8.

In general; if P(x) is a polynomial in x and k is any real number, then the value of P(k) at x = k is denoted by P(k) is found by replacing x by k in P(x).

In the polynomial x2 – 3x + 2,

Replacing x by 1 gives,

P(1) = 1 – 3 + 2 = 0

Similarly, replacing x by 2 gives,

P(2) = 4-6+2 = 0

For a polynomial P(x), real number k is said to be zero of polynomial P(x), if P(k) = 0.

Therefore, 1 and 2 are the zeros of polynomial x2 – 3x + 2.

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