Question

how to get the values of a and b from 4a+b+28=9 ?

Answer 1

Answer:

(divide both sides by b)

Then, at a+b=2 equation, replace a by 48/b

Hence u get 48b +b=2

Multiply all terms by b, u get

48+ b2 =2b

Get all of them in one side, with respect that any term moves from one side to another has to change its sign. Hence

\b2 -2b+48=0

Using the quadratic formula:

b=−B±B2−4AC√2A

In our case,

A = 1

B = -2

C = 48

Accordingly, B2 - 4AC =

4 - 192 =

-188

mark it Braillent friend

Answer 2

Answer:

b= 1.33, a= -19.33

Step-by-step explanation:

first find A

4a+b+28=9

=→ 4a+b= 9-28

=→ 4a= -19-b

=→ a= -19-b/4

Now find b

4a+b+28=9

=→ 4× -19-b/4+b+28= 9

=→ 4×-19-b/4+b= 9-28

=→4(4×-19-b+b)= 4(-19)

=→16-76-4b+4b= -76

=→ -4b+4b= -76+76-16

=→ -4b+4b= -16

=→ -4b+b= -16/4

=→ -3b= -4

=→ b= -4/-3

=→ b= 1.33

Now a= -19-b/4

= -19-(1.33)/4

= -19-1.33/4

= -19.33

Hope my answer helps you.