Question

how to make following solutions:
0.05 N NaOH 100 ml​

Answer 1

Answer:

Explanation:

First you need to decide how much you want to prepare. I’ll go for 1 L and for any thing else, just adjust the proportions accordingly.

You will need to calculate the molecular weight of sodium hydroxide (NaOH). The required atomic weights are 23, 16, 1 for Na, O, and H and this leads to a molecular weight for NaOH of 40 g/mole.

The desire is for a 0.05 N solution. For each mole of NaOH you get one equivalent of hydroxide (and sodium) so, for NaOH, normality and molarity are equivalent. Compare with something like Ca(OH)2. In this case, you get 2 moles of hydroxide for each mole of Ca(OH)2 and the normality of a 1 M solution of Ca(OH)2 is 2 (with respect to hydroxide).

One liter of a 0.05 N solution is the same as one liter of a 0.05 M solution of NaOH. So, you will need 0.05 moles of NaOH for on liter. 0.05 moles of NaOH is equal to 2 grams.

So, get a 1 liter volumetric. Place 2 g of NaOH in it and dilute to the mark. Done.

Answer 2

Given: Normality of solution 0.005N

           Quantity 100ml

First of all, we need to determine the molecular weight or equivalent weight of NaOH

           NaOH $=23+1+16$

     Molecular weight $=40$

This means that when 40gm of NaOH is dissolved in 1 litre solution will become 1N normality.

for 0.05N solution

    $0.01N=0.4gm$

   $0.005N=\frac{40\times 0.05}{0.1}$

              $=20gm$

Thus, 20gm NaOH is required to make solutions of 100ml and 0.05N

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