Question

How to make
$\sqrt{40}$
on number line​

Answer 1

Answer:

• do the same method as you do while constructing √2 on the number line.
• only the thing is you have to take 4 as (a) and 2 as (b).
• So (4)²=16 & (2)²=4

Answer 2

Step-by-step explanation:

Steps of construction:

1. Draw a line m and cut a 6 cm long segment OA from it.
2. On point A draw a perpendicular and cut a 2 cm long segment AB
3. Join OB.
4. Taking O as centre and OB as radius draw an arc which intersects the line m at a point say P
5. Point P will represent $\sqrt{40}$.

Explanation:

$In \: right \triangle \:OAB\\</p><p>OB^2 =OA^2+AB^2\\</p><p>\:\:\:\:\:\:\:\:\:\:\:=6^2 +2^2 =36+4=40</p><p>\\\implies OB= \sqrt {40}$