Chemistry, asked by eshaamukhtar, 9 months ago

How to prepare 2M stock of NaCl in 350mL (Molecular Weight=58.44g/mol)​

Answers

Answered by divyalokanathan2000
0

It can be prepared by mixing 40.9 g of NaCl in water to make 350 mL of solution.

Explanation:

Molarity,

M = X(wt. of solute).1000 / (Mol.wt. of solute)(V of soln in mL)

2 = X . 1000 /( 58.44) (350)

X = 2 x 58.44 x 350 / 1000 = 40.9 g of NaCl

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