Math, asked by mohitbohra1168, 1 year ago

How to prove (1+sin2A)/(cos2A)=(cosA+sinA)/(cosA-sinA)

Answers

Answered by sumo2

LHS=(1+sin2A)/(cos2A)
=(sin^2A+cos^2A+2sinAcosA)/(cos^2A-sin^2A)
=[(sinA+cosA)^2]/(cos^2A-sin^2A)
=(sinA+cosA)^2/(cosA+sinA)(cosA-sinA)
=(sinA+cosA)/(cosA-sinA)=RHS

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