Question

How to prove cube root of 6 is irrational???????????

Answer 1

let  cuberoot  of  6  be  rational =  a/b  where  a  and  b  are  integers  and  b not equl  to  zero.

cubing  both  sides  we  get   6=  a3/b3

a3 =  6  b3     both  numbers  on  right  hand  side  should  be  cubes

but  6  is  not