how to prove Sin 90°= coso
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Answered by
1
Answer:
Sin 90 = Cos0
Step-by-step explanation:
= Sin(90+0)
as Sin(90+ x)= Cos x
= Sin (90 + 0) = cos 0
Answered by
2
sin 90 = sin (30+60)
[sin (A+B) = sinAcosB+cosAsinB]
sin 90= sin30cos 60+cos30sin60
= (1/2)(1/2)+(√3/2)(√3/2)
= (1/4)+(3/4) = 1/1 = 1
= cos 0
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