Question

how to prove Sin 90°= coso
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Answer 1

Answer:

Sin 90 = Cos0

Step-by-step explanation:

= Sin(90+0)

as Sin(90+ x)= Cos x

= Sin (90 + 0) = cos 0

Answer 2

sin 90 = sin (30+60)

[sin (A+B) = sinAcosB+cosAsinB]

sin 90= sin30cos 60+cos30sin60

= (1/2)(1/2)+(√3/2)(√3/2)

= (1/4)+(3/4) = 1/1 = 1

= cos 0

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