How to prove that a number is irrational?
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let the number be 5-√3
first we have to assume the given number as rational number
then we have to write that number as 5-√3=p/q
and assume the both p and q as integers which have no common factor except 1
then after solving we will get 5-p/q=√3
then√3= 5q-p/q
then 5q-p/q is proved as rational no. which have p and q as integers
√3 is also a rational number which is a contradiction
Thus assumption is wrong
hence,5-√3 is an irrational number
We have to keep those steps in mind to prove a given number as irrational number.
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