how to prove that three points on two circles are collinear
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Hey mate!
Here's the solution....
: Join AB, BC, and BD.
: As we know, angle subtended by the diameter of a circle is 90°
So, <ABC=90°,because <ABC is is subtened by diameter AC.
And, <ABD=90°,because <ABD is is subtened by diameter AD.
<CBD=<ABC+<ABD
=90°+90°
=180°
Therefore, CBD is a straight line, and points C, B and D are collinear.
....Hence, proved.
I hope it helps you!!
Here's the solution....
: Join AB, BC, and BD.
: As we know, angle subtended by the diameter of a circle is 90°
So, <ABC=90°,because <ABC is is subtened by diameter AC.
And, <ABD=90°,because <ABD is is subtened by diameter AD.
<CBD=<ABC+<ABD
=90°+90°
=180°
Therefore, CBD is a straight line, and points C, B and D are collinear.
....Hence, proved.
I hope it helps you!!
chinmay20ac:
yeah thanks didi
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