Question

How to prove the third law of motion with graphical re?

Answer 1

Prove: v2−u2=2asv2−u2=2as
⟹a=vdvds⟹a=vdvds
⟹ads=vdv⟹ads=vdv
⟹a∫s0ds=∫vuvdv⟹a∫0sds=∫uvvdv
⟹as=v22∣∣∣vu⟹as=v22|uv
⟹2as=v2−u2⟹2as=v2−u2
where,
ss=Position or displacement
vv=Final velocity
uu=Initial velocity
aa=Acceleration(Constant)