Question

how to rationalize the denomineter of 1/ Underoot 3 - Underoot 2​

Answer 1

Answer:

♠️ Answer ♠️

$\frac{1}{ \sqrt{3} - \sqrt{2} } \\ \\ = multiply \: both \: numerator \: and \\ denominator \: by \: \sqrt{3} + \sqrt{2} \\ \\ \frac{1}{ \sqrt{3} - \sqrt{2} } \times \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} + \sqrt{2} } \\ \\ \frac{ \sqrt{3} + \sqrt{2} }{3 - 2} \\ \\ \frac{ \sqrt{3} + \sqrt{2} }{1}$

Answer 2

Answer:

root3+root2

Step-by-step explanation:

1/(root3-root2)

we should multiply the denominater as well as the numerater with the conjugate of the denomenator which is (root3+root2)

(root3+root2)/(3-2) because (a+b)(a-b)=(a^2-b^2)

so the answer is root3+root2/1