Question

How to ..relate electric field and potential difference.... ❤❤​

Answer 1

Answer:

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ᴛʜᴇ ʀᴇʟᴀᴛɪᴏɴsʜɪᴘ ʙᴇᴛᴡᴇᴇɴ ᴘᴏᴛᴇɴᴛɪᴀʟ ᴀɴᴅ ғɪᴇʟᴅ (ᴇ) ɪs ᴀ ᴅɪғғᴇʀᴇɴᴛɪᴀʟ: ᴇʟᴇᴄᴛʀɪᴄ ғɪᴇʟᴅ ɪs ᴛʜᴇ ɢʀᴀᴅɪᴇɴᴛ ᴏғ ᴘᴏᴛᴇɴᴛɪᴀʟ (ᴠ) ɪɴ ᴛʜᴇ x ᴅɪʀᴇᴄᴛɪᴏɴ. ᴛʜɪs ᴄᴀɴ ʙᴇ ʀᴇᴘʀᴇsᴇɴᴛᴇᴅ ᴀs: ᴇx=−ᴅᴠᴅx ᴇ x = − ᴅᴠ ᴅx . ᴛʜᴜs, ᴀs ᴛʜᴇ ᴛᴇsᴛ ᴄʜᴀʀɢᴇ ɪs ᴍᴏᴠᴇᴅ ɪɴ ᴛʜᴇ x ᴅɪʀᴇᴄᴛɪᴏɴ, ᴛʜᴇ ʀᴀᴛᴇ ᴏғ ᴛʜᴇ ɪᴛs ᴄʜᴀɴɢᴇ ɪɴ ᴘᴏᴛᴇɴᴛɪᴀʟ ɪs ᴛʜᴇ ᴠᴀʟᴜᴇ ᴏғ ᴛʜᴇ ᴇʟᴇᴄᴛʀɪᴄ ғɪᴇʟᴅ.

Answer 2

The relationship between potential and field (E) is a differential: electric field is the gradient of potential (V) in the x direction. This can be represented as: Ex=−dVdx E x = − dV dx . Thus, as the test charge is moved in the x direction, the rate of the its change in potential is the value of the electric field.

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