Question

How to represent (1+√9.5) on number line?

Answer 1

Here is your answer @User. ☺

--------------------

✴Step 1:
Draw 2 points A(1,0)A(1,0) and B(1.5,0.5)B(1.5,0.5)

According to the Pythagoras theorem, the length of AB would be

AB=|1−1.5|2+|0−0.5|2−−−−−−−−−−−−−−−
−−√=2√2.AB
=|1−1.5|2+|0−0.5|2
=22.

✴Step 2: Draw a circle centered at A and radius AB. Let C, D be the intersection points of the circle (A,AB)(A,AB) and the X-axis line. The coordinates of C and D would be:

C(1−2√2,0);C(1−22,0);

D(1+2√2,0).D(1+22,0).

✴Step 3:
Draw E(1,3)E(1,3) . The length of DE would be

DE=|1−(1+2√2)|2+|0−3|2−−−−−−−−−−−−−−−−−−−−√=9.5−−−√DE=|1−(1+22)|2+|0−3|2=9.5

✴Step 4:
Draw a circle centered at A that has a radius of DE. Let F, G be the intersection points of the circle (A, DE) and the X-axis line. The coordinates of F and G would be:

F(1−9.5−−−√,0)F(1−9.5,0)

G(1+9.5−−−√,0)G(1+9.5,0)

⭐Because the X-axis line is a number line, you have successfully represented the point 1+9.5−−−√1+9.5 on the number line.


Hope it helped you out ✴^_^✴
Thanks ✴(^^)✴