Question

if a=2+root3. then find the value of a-1/a???

Answer 1

$a = 2 + \sqrt{3} \\ {a - 1} \div a \\{{ 2 + \sqrt{3}} - 1} \div 2 + \sqrt{3 } \\ {{ 2 + \sqrt{3}} - 1} \times 2 - \sqrt{3} \div 2 + \sqrt{3 } \times 2 - \sqrt{3}$

Answer 2

Solution:-


$a = 2 + \sqrt{3 } \\ a - \frac{1}{a} \\ 2 + \sqrt{3} - \frac{1}{2 + \sqrt{3} } \\ \frac{4 + 3 + 4 \sqrt{3} - 1}{2 + \sqrt{3} } \\ \frac{6+ 4 \sqrt{3} }{2 + \sqrt{3} }$