How to represent √23 on number line
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This is easy, but tricky.
Use Pythagoras theorem.
Take a point 'p' at a distance of 1 unit from origin in the x axis and 'q' at adistance of 1 unit from origin in the y axis.
Join pq.. then length of 'pq' will be √2., by Pythagoras theorem.
Measure 'pq' using a compass and taking origin as center, draw an arc cutting x axis at r.
Then distance from origin to r will be √2.
join 'qr' . By Pythagoras theorem ,
qr= √3..
Next take √3 distance in x axis and 2 units in y axis .. repeat the above procedure , you will get √7.
Finally take √7 units in x axis and 4 units in y axis, repeat the above procedure, you will get √23.
Now measure the distance (√23)using compass, taking origin(o) as center draw an arc cutting x axis at m.
Distance on will be √23.
ok hard to type now so this is the answer
Use Pythagoras theorem.
Take a point 'p' at a distance of 1 unit from origin in the x axis and 'q' at adistance of 1 unit from origin in the y axis.
Join pq.. then length of 'pq' will be √2., by Pythagoras theorem.
Measure 'pq' using a compass and taking origin as center, draw an arc cutting x axis at r.
Then distance from origin to r will be √2.
join 'qr' . By Pythagoras theorem ,
qr= √3..
Next take √3 distance in x axis and 2 units in y axis .. repeat the above procedure , you will get √7.
Finally take √7 units in x axis and 4 units in y axis, repeat the above procedure, you will get √23.
Now measure the distance (√23)using compass, taking origin(o) as center draw an arc cutting x axis at m.
Distance on will be √23.
ok hard to type now so this is the answer
yasir20:
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