How to represent 5 root 2 on number line by spiral method ?
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draw a number line.take a point A andO on it.points A and O represents 0 and 1 respectively.draw 1 cm perpendicular to the number line at A.join OB
.
in right angled triangle OBA
we have,
OB2=OA2+BA2
=12+12
=1+1
=2
OB2=2
OB=sqaure root of 2
taking O as centre and radius root 2 draw an arc which intersect the nummber line at P.
Therfore,OP=root 2 units
.
in right angled triangle OBA
we have,
OB2=OA2+BA2
=12+12
=1+1
=2
OB2=2
OB=sqaure root of 2
taking O as centre and radius root 2 draw an arc which intersect the nummber line at P.
Therfore,OP=root 2 units
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